2q^2+1.5q+17=43

Solution for 2q^2+1.5q+17=43 equation:

2q^2+1.5q+17=43

We move all terms to the left:

2q^2+1.5q+17-(43)=0

We add all the numbers together, and all the variables

2q^2+1.5q-26=0

a = 2; b = 1.5; c = -26;
Δ = b2-4ac
Δ = 1.52-4·2·(-26)
Δ = 210.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.5)-\sqrt{210.25}}{2*2}=\frac{-1.5-\sqrt{210.25}}{4}
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.5)+\sqrt{210.25}}{2*2}=\frac{-1.5+\sqrt{210.25}}{4}
$